(18r^2=)^0

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Solution for (18r^2=)^0 equation: 



(18r^2=)^0

We move all terms to the left:

(18r^2-()^0)=0



We calculate terms in parentheses: +(18r^2-()^0), so:

18r^2-()^0

We add all the numbers together, and all the variables

18r^2

Back to the equation:

+(18r^2)



a = 18; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·18·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{36}=0$

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